What are the solutions to the equation x^2-5=8-2x^2 ?

The solutions to the equation x^2-5=8-2x^2 are x=sqrt(13/3),x=-sqrt(13/3)

Find the zeros of x^2-5=8-2x^2

The zeros of x^2-5=8-2x^2 are x=sqrt(13/3),x=-sqrt(13/3)

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x^{2} - 5 = 8 - 2 x^{2}

x = \frac{13}{3}, x = - \frac{13}{3}

Decimal Notation

x = 2.08166 \dots, x = - 2.08166 \dots

Solution steps

x^{2} - 5 = 8 - 2 x^{2}

Move

5

to the right side

x^{2} = - 2 x^{2} + 13

Move

2 x^{2}

to the left side

3 x^{2} = 13

Divide both sides by

3

x^{2} = \frac{13}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{13}{3}, x = - \frac{13}{3}

5 x (x - 2) = 6 + 3 x

x, x^{2} - 15 - m (2 x - 8) = 0

x^{2} - 5 x + 3 = 0

5 x^{2} + 10 x + 8 = 0

3 x^{2} + 10 x + 73 = 0

What are the solutions to the equation x^2-5=8-2x^2 ?
The solutions to the equation x^2-5=8-2x^2 are x=sqrt(13/3),x=-sqrt(13/3)
Find the zeros of x^2-5=8-2x^2
The zeros of x^2-5=8-2x^2 are x=sqrt(13/3),x=-sqrt(13/3)