What are the solutions to the equation (6-x)(x+1)=0 ?

The solutions to the equation (6-x)(x+1)=0 are x=6,x=-1

Find the zeros of (6-x)(x+1)=0

The zeros of (6-x)(x+1)=0 are x=6,x=-1

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(6 - x) (x + 1) = 0

x = 6, x = - 1

Solution steps

(6 - x) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 - x = 0 or x + 1 = 0

Solve

6 - x = 0 : x = 6

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

0 = 210 + 205.06 x - 4.9 x^{2}

(x - 1)^{2} - 64 = 0

2 (x + 1)^{2} - 3 (x + 1) + 1 = 0

x^{2} + \frac{1}{3} x + 2 = 0

(x + 5)^{2} - 81 = 0

What are the solutions to the equation (6-x)(x+1)=0 ?
The solutions to the equation (6-x)(x+1)=0 are x=6,x=-1
Find the zeros of (6-x)(x+1)=0
The zeros of (6-x)(x+1)=0 are x=6,x=-1