What are the solutions to the equation 0=-x^2+x+2 ?

The solutions to the equation 0=-x^2+x+2 are x=-1,x=2

Find the zeros of 0=-x^2+x+2

The zeros of 0=-x^2+x+2 are x=-1,x=2

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0 = - x^{2} + x + 2

x = - 1, x = 2

Solution steps

0 = - x^{2} + x + 2

Switch sides

- x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3}{2 ( - 1 )}

x = \frac{- 1 + 3}{2 ( - 1 )} : - 1

x = \frac{- 1 - 3}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

- 6 x^{2} - 24 x + 564 = 0

(36 - 2 r)^{2} = 36 + 2 r

(x + 5)^{2} = x + 7

8 x^{2} + 3 - 6 x = 5 x^{2}

3 (y - 4)^{2} = 192

What are the solutions to the equation 0=-x^2+x+2 ?
The solutions to the equation 0=-x^2+x+2 are x=-1,x=2
Find the zeros of 0=-x^2+x+2
The zeros of 0=-x^2+x+2 are x=-1,x=2