What are the solutions to the equation 2x^2+5=3 ?

The solutions to the equation 2x^2+5=3 are x=i,x=-i

Find the zeros of 2x^2+5=3

The zeros of 2x^2+5=3 are x=i,x=-i

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2 x^{2} + 5 = 3

x = i, x = - i

Solution steps

2 x^{2} + 5 = 3

Move

5

to the right side

2 x^{2} = - 2

Divide both sides by

2

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

10 x^{2} - 256 = 300

9 x^{2} = 18

(k - (- 1)) (k + 1) = - 13 (- 1) - 2 k

n^{2} + 2 n + 4 = 33

z^{2} - 10 z + 45 = 5

What are the solutions to the equation 2x^2+5=3 ?
The solutions to the equation 2x^2+5=3 are x=i,x=-i
Find the zeros of 2x^2+5=3
The zeros of 2x^2+5=3 are x=i,x=-i