What are the solutions to the equation completesquare 3x^2+5x-28=0 ?

The solutions to the equation completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4

Find the zeros of completesquare 3x^2+5x-28=0

The zeros of completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 5 x - 28 = 0

x = \frac{7}{3}, x = - 4

Decimal Notation

x = 2.33333 \dots, x = - 4

Solution steps

3 x^{2} + 5 x - 28 = 0

Move

28

to the right side

3 x^{2} + 5 x = 28

Divide both sides by

3

\frac{3 x ^{2} + 5 x}{3} = \frac{28}{3}

x^{2} + \frac{5 x}{3} = \frac{28}{3}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{6})^{2} = \frac{361}{36}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{6} = \frac{361}{36} : x = \frac{7}{3}

Solve

x + \frac{5}{6} = - \frac{361}{36} : x = - 4

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 4

(1 + 5 x)^{2} = (4 x - 1) 2^{2} + 9 x (x - 2)

4 x + x^{2} = x - 3

x, y = 3 x^{2} - 30 x + 72

- 2 x^{2} + 2 x + 13 = 0

x^{2} - 2.454 x + 1.25 = 0

What are the solutions to the equation completesquare 3x^2+5x-28=0 ?
The solutions to the equation completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4
Find the zeros of completesquare 3x^2+5x-28=0
The zeros of completesquare 3x^2+5x-28=0 are x= 7/3 ,x=-4