What are the solutions to the equation 3x^2-116x+980=0 ?

The solutions to the equation 3x^2-116x+980=0 are x=(2(29+sqrt(106)))/3 ,x=(2(29-sqrt(106)))/3

Find the zeros of 3x^2-116x+980=0

The zeros of 3x^2-116x+980=0 are x=(2(29+sqrt(106)))/3 ,x=(2(29-sqrt(106)))/3

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3 x^{2} - 116 x + 980 = 0

x = \frac{2 ( 29 + 106 )}{3}, x = \frac{2 ( 29 - 106 )}{3}

Decimal Notation

x = 26.19708 \dots, x = 12.46957 \dots

Solution steps

3 x^{2} - 116 x + 980 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 116 ) \pm ( - 116 ) ^{2} - 4 \cdot 3 \cdot 980}{2 \cdot 3}

(- 116)^{2} - 4 \cdot 3 \cdot 980 = 4106

x_{1, 2} = \frac{- ( - 116 ) \pm 4 106}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 116 ) + 4 106}{2 \cdot 3}, x_{2} = \frac{- ( - 116 ) - 4 106}{2 \cdot 3}

x = \frac{- ( - 116 ) + 4 106}{2 \cdot 3} : \frac{2 ( 29 + 106 )}{3}

x = \frac{- ( - 116 ) - 4 106}{2 \cdot 3} : \frac{2 ( 29 - 106 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 29 + 106 )}{3}, x = \frac{2 ( 29 - 106 )}{3}

0 = 9 x^{2} - 12 x

t, h = \frac{1}{2} a t^{2}

10 x^{2} - 2 x - 1

x^{2} + 3 x - 25 = 0

x^{2} = - 11 x + 80

What are the solutions to the equation 3x^2-116x+980=0 ?
The solutions to the equation 3x^2-116x+980=0 are x=(2(29+sqrt(106)))/3 ,x=(2(29-sqrt(106)))/3
Find the zeros of 3x^2-116x+980=0
The zeros of 3x^2-116x+980=0 are x=(2(29+sqrt(106)))/3 ,x=(2(29-sqrt(106)))/3