What are the solutions to the equation -8=x^2 ?

The solutions to the equation -8=x^2 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of -8=x^2

The zeros of -8=x^2 are x=2sqrt(2)i,x=-2sqrt(2)i

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- 8 = x^{2}

x = 22 i, x = - 22 i

Solution steps

- 8 = x^{2}

Switch sides

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

2 (u + 1) + 4 u = 3 (2 u - 1) + 8

x y + 2 y + 3 x + 6

5 \cdot (x + 1) + 4 \cdot (2 x - 3) = 6

lo g_{a} (1)

\frac{\frac{- 4}{3} - 3}{1 + ( - \frac{4}{3} ) ( 3 )}

What are the solutions to the equation -8=x^2 ?
The solutions to the equation -8=x^2 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of -8=x^2
The zeros of -8=x^2 are x=2sqrt(2)i,x=-2sqrt(2)i