What are the solutions to the equation 20(p^2-1)=9p ?

The solutions to the equation 20(p^2-1)=9p are p= 5/4 ,p=-4/5

Find the zeros of 20(p^2-1)=9p

The zeros of 20(p^2-1)=9p are p= 5/4 ,p=-4/5

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20 (p^{2} - 1) = 9 p

p = \frac{5}{4}, p = - \frac{4}{5}

Decimal Notation

p = 1.25, p = - 0.8

Solution steps

20 (p^{2} - 1) = 9 p

Expand

20 (p^{2} - 1) : 20 p^{2} - 20

20 p^{2} - 20 = 9 p

Move

9 p

to the left side

20 p^{2} - 20 - 9 p = 0

Write in the standard form

a x^{2} + b x + c = 0

20 p^{2} - 9 p - 20 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 20 ( - 20 )}{2 \cdot 20}

(- 9)^{2} - 4 \cdot 20 (- 20) = 41

p_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 \cdot 20}

Separate the solutions

p_{1} = \frac{- ( - 9 ) + 41}{2 \cdot 20}, p_{2} = \frac{- ( - 9 ) - 41}{2 \cdot 20}

p = \frac{- ( - 9 ) + 41}{2 \cdot 20} : \frac{5}{4}

p = \frac{- ( - 9 ) - 41}{2 \cdot 20} : - \frac{4}{5}

The solutions to the quadratic equation are:

p = \frac{5}{4}, p = - \frac{4}{5}

- d^{2} + 200 = d^{2} - 42

5 x^{2} - 29 x + 20 = 0

2 x^{2} = - 7 x - 9

2 x^{2} = - 7 x + 4

4 v^{2} = 9

What are the solutions to the equation 20(p^2-1)=9p ?
The solutions to the equation 20(p^2-1)=9p are p= 5/4 ,p=-4/5
Find the zeros of 20(p^2-1)=9p
The zeros of 20(p^2-1)=9p are p= 5/4 ,p=-4/5