What are the solutions to the equation 8x^2+1=22x+1 ?

The solutions to the equation 8x^2+1=22x+1 are x= 11/4 ,x=0

Find the zeros of 8x^2+1=22x+1

The zeros of 8x^2+1=22x+1 are x= 11/4 ,x=0

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8 x^{2} + 1 = 22 x + 1

x = \frac{11}{4}, x = 0

Decimal Notation

x = 2.75, x = 0

Solution steps

8 x^{2} + 1 = 22 x + 1

Move

1

to the left side

8 x^{2} = 22 x

Move

22 x

to the left side

8 x^{2} - 22 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 22)^{2} - 4 \cdot 8 \cdot 0 = 22

x_{1, 2} = \frac{- ( - 22 ) \pm 22}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 22}{2 \cdot 8}, x_{2} = \frac{- ( - 22 ) - 22}{2 \cdot 8}

x = \frac{- ( - 22 ) + 22}{2 \cdot 8} : \frac{11}{4}

x = \frac{- ( - 22 ) - 22}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{11}{4}, x = 0

4 (x + 3)^{2} = 25 (x - 2)^{2}

x, x^{2} - 6 x y + y^{2} = 0

x, 2 p x^{2} + 3 x - 2 - 5 p = 0

25 (x + 1) = \frac{7}{2} x^{2}

1 x^{2} + x + 1 = 0

What are the solutions to the equation 8x^2+1=22x+1 ?
The solutions to the equation 8x^2+1=22x+1 are x= 11/4 ,x=0
Find the zeros of 8x^2+1=22x+1
The zeros of 8x^2+1=22x+1 are x= 11/4 ,x=0