What are the solutions to the equation 4x=-4x^2 ?

The solutions to the equation 4x=-4x^2 are x=0,x=-1

Find the zeros of 4x=-4x^2

The zeros of 4x=-4x^2 are x=0,x=-1

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4 x = - 4 x^{2}

x = 0, x = - 1

Solution steps

4 x = - 4 x^{2}

Move

4 x^{2}

to the left side

4 x + 4 x^{2} = 0

Factor

4 x + 4 x^{2} : 4 x (x + 1)

4 x (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

x^{2} - 2 x - 1 = 0

x, f (2 x + 1) = 1 - (x - 3)^{2}

x, 12 x^{2} = 3 x

p^{2} - 169 = 0

x^{2} + 3 + 4 + 2 x = 15

What are the solutions to the equation 4x=-4x^2 ?
The solutions to the equation 4x=-4x^2 are x=0,x=-1
Find the zeros of 4x=-4x^2
The zeros of 4x=-4x^2 are x=0,x=-1