What are the solutions to the equation -z^2=4 ?

The solutions to the equation -z^2=4 are z=2i,z=-2i

Find the zeros of -z^2=4

The zeros of -z^2=4 are z=2i,z=-2i

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- z^{2} = 4

z = 2 i, z = - 2 i

Solution steps

- z^{2} = 4

Divide both sides by

- 1

z^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 4, z = - - 4

- 4 = 2 i

- - 4 = - 2 i

z = 2 i, z = - 2 i

5 x^{2} + 2 = 2 x

t^{2} - 3 t - 7 = 0

x, E = \frac{1}{2} k x^{2}

x, t (x) = - x^{2} + 4 x - 5

x^{2} + 1 5^{2} = 2 5^{2}

What are the solutions to the equation -z^2=4 ?
The solutions to the equation -z^2=4 are z=2i,z=-2i
Find the zeros of -z^2=4
The zeros of -z^2=4 are z=2i,z=-2i