What are the solutions to the equation 7x-2x^2=0 ?

The solutions to the equation 7x-2x^2=0 are x=0,x= 7/2

Find the zeros of 7x-2x^2=0

The zeros of 7x-2x^2=0 are x=0,x= 7/2

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7 x - 2 x^{2} = 0

x = 0, x = \frac{7}{2}

Decimal Notation

x = 0, x = 3.5

Solution steps

7 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 ( - 2 )}, x_{2} = \frac{- 7 - 7}{2 ( - 2 )}

x = \frac{- 7 + 7}{2 ( - 2 )} : 0

x = \frac{- 7 - 7}{2 ( - 2 )} : \frac{7}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{7}{2}

- 3 y^{2} + 3 = 0

5 x^{2} = 8 - 7 x

x^{2} - 2 x + 3 = 11

3 n^{2} + n = 400

1 = x^{2} - 6

What are the solutions to the equation 7x-2x^2=0 ?
The solutions to the equation 7x-2x^2=0 are x=0,x= 7/2
Find the zeros of 7x-2x^2=0
The zeros of 7x-2x^2=0 are x=0,x= 7/2