What are the solutions to the equation 3r^2+r-9=-2 ?

The solutions to the equation 3r^2+r-9=-2 are r=(-1+sqrt(85))/6 ,r=(-1-sqrt(85))/6

Find the zeros of 3r^2+r-9=-2

The zeros of 3r^2+r-9=-2 are r=(-1+sqrt(85))/6 ,r=(-1-sqrt(85))/6

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3 r^{2} + r - 9 = - 2

r = \frac{- 1 + 85}{6}, r = \frac{- 1 - 85}{6}

Decimal Notation

r = 1.36992 \dots, r = - 1.70325 \dots

Solution steps

3 r^{2} + r - 9 = - 2

Move

2

to the left side

3 r^{2} + r - 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 7) = 85

r_{1, 2} = \frac{- 1 \pm 85}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- 1 + 85}{2 \cdot 3}, r_{2} = \frac{- 1 - 85}{2 \cdot 3}

r = \frac{- 1 + 85}{2 \cdot 3} : \frac{- 1 + 85}{6}

r = \frac{- 1 - 85}{2 \cdot 3} : \frac{- 1 - 85}{6}

The solutions to the quadratic equation are:

r = \frac{- 1 + 85}{6}, r = \frac{- 1 - 85}{6}

5 (x^{2} + 2) - 8 = 7

x^{2} + 10 x - 4

3 y^{2} - y + 4 = 0

x^{2} - 9 ab x + 20 a^{2} b^{2} = 0

3 v^{2} - 27 v = 0

What are the solutions to the equation 3r^2+r-9=-2 ?
The solutions to the equation 3r^2+r-9=-2 are r=(-1+sqrt(85))/6 ,r=(-1-sqrt(85))/6
Find the zeros of 3r^2+r-9=-2
The zeros of 3r^2+r-9=-2 are r=(-1+sqrt(85))/6 ,r=(-1-sqrt(85))/6