What are the solutions to the equation 1x^2-1x-6=0 ?

The solutions to the equation 1x^2-1x-6=0 are x=3,x=-2

Find the zeros of 1x^2-1x-6=0

The zeros of 1x^2-1x-6=0 are x=3,x=-2

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1 x^{2} - 1 x - 6 = 0

x = 3, x = - 2

Solution steps

1 \cdot x^{2} - 1 \cdot x - 6 = 0

Refine

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

x^{2} + 9 x^{2} + 8 = 0

x^{2} + 1 0^{2} = 2 0^{2}

x^{2} - 10 x - 96

0 = 5 x^{2} - 7

x, x^{2} + y^{2} - 4 x + 8 = 0

What are the solutions to the equation 1x^2-1x-6=0 ?
The solutions to the equation 1x^2-1x-6=0 are x=3,x=-2
Find the zeros of 1x^2-1x-6=0
The zeros of 1x^2-1x-6=0 are x=3,x=-2