What are the solutions to the equation x(x+1)=650 ?

The solutions to the equation x(x+1)=650 are x=25,x=-26

Find the zeros of x(x+1)=650

The zeros of x(x+1)=650 are x=25,x=-26

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x (x + 1) = 650

x = 25, x = - 26

Solution steps

x (x + 1) = 650

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 650

Move

650

to the left side

x^{2} + x - 650 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 650 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 650) = 51

x_{1, 2} = \frac{- 1 \pm 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 51}{2 \cdot 1}, x_{2} = \frac{- 1 - 51}{2 \cdot 1}

x = \frac{- 1 + 51}{2 \cdot 1} : 25

x = \frac{- 1 - 51}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

x = 25, x = - 26

x, z = 16 - x^{2} - 2 y^{2}

x (2 x + 5) = 12

x (2 x + 5) = 15

x^{2} - 48 = 11

3 x^{2} - 3 = - 111

What are the solutions to the equation x(x+1)=650 ?
The solutions to the equation x(x+1)=650 are x=25,x=-26
Find the zeros of x(x+1)=650
The zeros of x(x+1)=650 are x=25,x=-26