What are the solutions to the equation (x^2)/2+2x-6=0 ?

The solutions to the equation (x^2)/2+2x-6=0 are x=2,x=-6

Find the zeros of (x^2)/2+2x-6=0

The zeros of (x^2)/2+2x-6=0 are x=2,x=-6

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\frac{x ^{2}}{2} + 2 x - 6 = 0

x = 2, x = - 6

Solution steps

\frac{x ^{2}}{2} + 2 x - 6 = 0

Multiply both sides by

2

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

x, 3 x^{2} + 4 y^{2} + 3 = 0

16 x^{2} + k x - h = 0

1 = 2 + x - x^{2}

r^{2} + 3 r - 54 = 0

x, f (a + b) = x^{2} - 5 x + 6

What are the solutions to the equation (x^2)/2+2x-6=0 ?
The solutions to the equation (x^2)/2+2x-6=0 are x=2,x=-6
Find the zeros of (x^2)/2+2x-6=0
The zeros of (x^2)/2+2x-6=0 are x=2,x=-6