What are the solutions to the equation z^2+5z+3=0 ?

The solutions to the equation z^2+5z+3=0 are z=(-5+sqrt(13))/2 ,z=(-5-sqrt(13))/2

Find the zeros of z^2+5z+3=0

The zeros of z^2+5z+3=0 are z=(-5+sqrt(13))/2 ,z=(-5-sqrt(13))/2

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z^{2} + 5 z + 3 = 0

z = \frac{- 5 + 13}{2}, z = \frac{- 5 - 13}{2}

Decimal Notation

z = - 0.69722 \dots, z = - 4.30277 \dots

Solution steps

z^{2} + 5 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 3 = 13

z_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 5 + 13}{2 \cdot 1}, z_{2} = \frac{- 5 - 13}{2 \cdot 1}

z = \frac{- 5 + 13}{2 \cdot 1} : \frac{- 5 + 13}{2}

z = \frac{- 5 - 13}{2 \cdot 1} : \frac{- 5 - 13}{2}

The solutions to the quadratic equation are:

z = \frac{- 5 + 13}{2}, z = \frac{- 5 - 13}{2}

x, 2 x^{2} + 5 x - 8 = 0

4 x (x - 4) = 7

- 15 t^{2} + 2 = - 7 t

(x - 4) (x + 6) - (x - 3) 2 = 15

\frac{1}{3} x - 4 = x^{2}

What are the solutions to the equation z^2+5z+3=0 ?
The solutions to the equation z^2+5z+3=0 are z=(-5+sqrt(13))/2 ,z=(-5-sqrt(13))/2
Find the zeros of z^2+5z+3=0
The zeros of z^2+5z+3=0 are z=(-5+sqrt(13))/2 ,z=(-5-sqrt(13))/2