What are the solutions to the equation x^2+2x+6=0 ?

The solutions to the equation x^2+2x+6=0 are x=-1+sqrt(5)i,x=-1-sqrt(5)i

Find the zeros of x^2+2x+6=0

The zeros of x^2+2x+6=0 are x=-1+sqrt(5)i,x=-1-sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x + 6 = 0

x = - 1 + 5 i, x = - 1 - 5 i

Solution steps

x^{2} + 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

x = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

x = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

x = - 1 + 5 i, x = - 1 - 5 i

\frac{2}{7} v + \frac{4}{5} = \frac{6}{5} v - \frac{4}{5}

40 x y + 15 y^{2}

\frac{2 b - 1}{2} - \frac{1 + 5 b}{4} < 0

\frac{13}{78} \cdot \frac{12}{5}

- 0.5 (x - 4) = - x - 5

What are the solutions to the equation x^2+2x+6=0 ?
The solutions to the equation x^2+2x+6=0 are x=-1+sqrt(5)i,x=-1-sqrt(5)i
Find the zeros of x^2+2x+6=0
The zeros of x^2+2x+6=0 are x=-1+sqrt(5)i,x=-1-sqrt(5)i