What are the solutions to the equation 5t^2-60t+27=0 ?

The solutions to the equation 5t^2-60t+27=0 are t=(3(10+sqrt(85)))/5 ,t=(3(10-sqrt(85)))/5

Find the zeros of 5t^2-60t+27=0

The zeros of 5t^2-60t+27=0 are t=(3(10+sqrt(85)))/5 ,t=(3(10-sqrt(85)))/5

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5 t^{2} - 60 t + 27 = 0

t = \frac{3 ( 10 + 85 )}{5}, t = \frac{3 ( 10 - 85 )}{5}

Decimal Notation

t = 11.53172 \dots, t = 0.46827 \dots

Solution steps

5 t^{2} - 60 t + 27 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 5 \cdot 27}{2 \cdot 5}

(- 60)^{2} - 4 \cdot 5 \cdot 27 = 685

t_{1, 2} = \frac{- ( - 60 ) \pm 6 85}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 60 ) + 6 85}{2 \cdot 5}, t_{2} = \frac{- ( - 60 ) - 6 85}{2 \cdot 5}

t = \frac{- ( - 60 ) + 6 85}{2 \cdot 5} : \frac{3 ( 10 + 85 )}{5}

t = \frac{- ( - 60 ) - 6 85}{2 \cdot 5} : \frac{3 ( 10 - 85 )}{5}

The solutions to the quadratic equation are:

t = \frac{3 ( 10 + 85 )}{5}, t = \frac{3 ( 10 - 85 )}{5}

(x - 2)^{2} - 5 = - 6

x, f (x + 3) = 3 x^{2} + 4 x - 2

3 x^{2} = - 12 x - 5

h^{2} + 6 h = 16

(x - 1) (x + 1) = 2 x - 3

What are the solutions to the equation 5t^2-60t+27=0 ?
The solutions to the equation 5t^2-60t+27=0 are t=(3(10+sqrt(85)))/5 ,t=(3(10-sqrt(85)))/5
Find the zeros of 5t^2-60t+27=0
The zeros of 5t^2-60t+27=0 are t=(3(10+sqrt(85)))/5 ,t=(3(10-sqrt(85)))/5