What are the solutions to the equation 4w^2=25w+21 ?

The solutions to the equation 4w^2=25w+21 are w=7,w=-3/4

Find the zeros of 4w^2=25w+21

The zeros of 4w^2=25w+21 are w=7,w=-3/4

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4 w^{2} = 25 w + 21

w = 7, w = - \frac{3}{4}

Decimal Notation

w = 7, w = - 0.75

Solution steps

4 w^{2} = 25 w + 21

Move

21

to the left side

4 w^{2} - 21 = 25 w

Move

25 w

to the left side

4 w^{2} - 21 - 25 w = 0

Write in the standard form

a x^{2} + b x + c = 0

4 w^{2} - 25 w - 21 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 4 ( - 21 )}{2 \cdot 4}

(- 25)^{2} - 4 \cdot 4 (- 21) = 31

w_{1, 2} = \frac{- ( - 25 ) \pm 31}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 25 ) + 31}{2 \cdot 4}, w_{2} = \frac{- ( - 25 ) - 31}{2 \cdot 4}

w = \frac{- ( - 25 ) + 31}{2 \cdot 4} : 7

w = \frac{- ( - 25 ) - 31}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

w = 7, w = - \frac{3}{4}

2 x + 24 = x^{2}

b^{2} + 2 b = - 22

(3 x - 2)^{2} - 11 = 25

5 - 2 x^{2} = 4 x

x^{2} + 8 = - 41

What are the solutions to the equation 4w^2=25w+21 ?
The solutions to the equation 4w^2=25w+21 are w=7,w=-3/4
Find the zeros of 4w^2=25w+21
The zeros of 4w^2=25w+21 are w=7,w=-3/4