What are the solutions to the equation solvefor y,x-y^2=4 ?

The solutions to the equation solvefor y,x-y^2=4 are y=sqrt(-4+x),y=-sqrt(-4+x)

Find the zeros of solvefor y,x-y^2=4

The zeros of solvefor y,x-y^2=4 are y=sqrt(-4+x),y=-sqrt(-4+x)

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solve for

y, x - y^{2} = 4

y = - 4 + x, y = - - 4 + x

Solution steps

x - y^{2} = 4

Move

x

to the right side

- y^{2} = 4 - x

Divide both sides by

- 1

y^{2} = - 4 + x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4 + x, y = - - 4 + x

x^{2} - 4 x + 130 = 14 x

p^{2} - 196 = 0

v^{2} = - 5 v - 4

x, f^{- 1} (x) = x^{2} + 1

x, f^{- 1} (x) = x^{2} - 2

What are the solutions to the equation solvefor y,x-y^2=4 ?
The solutions to the equation solvefor y,x-y^2=4 are y=sqrt(-4+x),y=-sqrt(-4+x)
Find the zeros of solvefor y,x-y^2=4
The zeros of solvefor y,x-y^2=4 are y=sqrt(-4+x),y=-sqrt(-4+x)