What are the solutions to the equation (x-2)^2=4-9x ?

The solutions to the equation (x-2)^2=4-9x are x=0,x=-5

Find the zeros of (x-2)^2=4-9x

The zeros of (x-2)^2=4-9x are x=0,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 2)^{2} = 4 - 9 x

x = 0, x = - 5

Solution steps

(x - 2)^{2} = 4 - 9 x

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} - 4 x + 4 = 4 - 9 x

Move

9 x

to the left side

x^{2} + 5 x + 4 = 4

Move

4

to the left side

x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : 0

x = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 0, x = - 5

A = 5 x (3 x + 2)

- 7 x^{2} + 4 x + \frac{2}{5} = 0

(x - 2)^{2} - 72 = 0

x^{2} = 5 (x + 210)

6 x^{2} - 5 x = 1

What are the solutions to the equation (x-2)^2=4-9x ?
The solutions to the equation (x-2)^2=4-9x are x=0,x=-5
Find the zeros of (x-2)^2=4-9x
The zeros of (x-2)^2=4-9x are x=0,x=-5