What are the solutions to the equation y(4-y)=0 ?

The solutions to the equation y(4-y)=0 are y=0,y=4

Find the zeros of y(4-y)=0

The zeros of y(4-y)=0 are y=0,y=4

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y (4 - y) = 0

y = 0, y = 4

Solution steps

y (4 - y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 4 - y = 0

Solve

4 - y = 0 : y = 4

The solutions to the quadratic equation are:

y = 0, y = 4

\frac{1}{4} x^{2} = 2 x^{2}

a^{2} - a + \frac{1}{4} = 0

x^{2} - 7 x + \frac{49}{4} = 0

x^{2} - 8 x + 16 = 12

x^{2} = 5 (x + 360)

What are the solutions to the equation y(4-y)=0 ?
The solutions to the equation y(4-y)=0 are y=0,y=4
Find the zeros of y(4-y)=0
The zeros of y(4-y)=0 are y=0,y=4