What are the solutions to the equation 2x^2+6x=-8 ?

The solutions to the equation 2x^2+6x=-8 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2

Find the zeros of 2x^2+6x=-8

The zeros of 2x^2+6x=-8 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2

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2 x^{2} + 6 x = - 8

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

Solution steps

2 x^{2} + 6 x = - 8

Move

8

to the left side

2 x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

6^{2} - 4 \cdot 2 \cdot 8 : 27 i

x_{1, 2} = \frac{- 6 \pm 2 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 7 i}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 7 i}{2 \cdot 2}

x = \frac{- 6 + 2 7 i}{2 \cdot 2} : - \frac{3}{2} + i \frac{7}{2}

x = \frac{- 6 - 2 7 i}{2 \cdot 2} : - \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

- x^{2} + 6 x + 7

(- \frac{5}{13})^{2} + y^{2} = 1

- x^{2} + 6 x - 7

x^{2} - 37 = 0

10 m^{2} + 4 m + 3920 = 0

What are the solutions to the equation 2x^2+6x=-8 ?
The solutions to the equation 2x^2+6x=-8 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2
Find the zeros of 2x^2+6x=-8
The zeros of 2x^2+6x=-8 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2