What are the solutions to the equation -2+4k^2=-15 ?

The solutions to the equation -2+4k^2=-15 are k=(sqrt(13))/2 i,k=-(sqrt(13))/2 i

Find the zeros of -2+4k^2=-15

The zeros of -2+4k^2=-15 are k=(sqrt(13))/2 i,k=-(sqrt(13))/2 i

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- 2 + 4 k^{2} = - 15

k = \frac{13}{2} i, k = - \frac{13}{2} i

Solution steps

- 2 + 4 k^{2} = - 15

Move

2

to the right side

4 k^{2} = - 13

Divide both sides by

4

k^{2} = - \frac{13}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = - \frac{13}{4}, k = - - \frac{13}{4}

- \frac{13}{4} = \frac{13}{2} i

- - \frac{13}{4} = - \frac{13}{2} i

k = \frac{13}{2} i, k = - \frac{13}{2} i

- (2 x^{2} + 7) = (2 x + 1) (x + 3)

0 = 4 x^{2} + 8 x + 4

x^{2} = 8 x - 19

x^{2} = 8 x - 23

- 10 x^{2} - 11 x + 6 = 0

What are the solutions to the equation -2+4k^2=-15 ?
The solutions to the equation -2+4k^2=-15 are k=(sqrt(13))/2 i,k=-(sqrt(13))/2 i
Find the zeros of -2+4k^2=-15
The zeros of -2+4k^2=-15 are k=(sqrt(13))/2 i,k=-(sqrt(13))/2 i