What are the solutions to the equation 5y^2=-12y ?

The solutions to the equation 5y^2=-12y are y=0,y=-12/5

Find the zeros of 5y^2=-12y

The zeros of 5y^2=-12y are y=0,y=-12/5

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5 y^{2} = - 12 y

y = 0, y = - \frac{12}{5}

Decimal Notation

y = 0, y = - 2.4

Solution steps

5 y^{2} = - 12 y

Move

12 y

to the left side

5 y^{2} + 12 y = 0

Factor

5 y^{2} + 12 y : y (5 y + 12)

y (5 y + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 5 y + 12 = 0

Solve

5 y + 12 = 0 : y = - \frac{12}{5}

The solutions to the quadratic equation are:

y = 0, y = - \frac{12}{5}

x^{2} + 12 + 36 = 0

5 x^{2} - 9 x - 4 = 0

x^{2} + (m - 1) x + 2 - m = 0

10 x^{2} - 24 x + 9 = 0

- 3 x^{2} - 18 x - 35

What are the solutions to the equation 5y^2=-12y ?
The solutions to the equation 5y^2=-12y are y=0,y=-12/5
Find the zeros of 5y^2=-12y
The zeros of 5y^2=-12y are y=0,y=-12/5