What are the solutions to the equation x^2-1x-12=0 ?

The solutions to the equation x^2-1x-12=0 are x=4,x=-3

Find the zeros of x^2-1x-12=0

The zeros of x^2-1x-12=0 are x=4,x=-3

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x^{2} - 1 x - 12 = 0

x = 4, x = - 3

Solution steps

x^{2} - 1 \cdot x - 12 = 0

Refine

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

x, 2 = 3 x^{2} - 4 y^{3}

x^{2} - 10 x = 5

x, f^{2} (x) = 2 x^{2} - 1

y, x^{2} + y^{2} - 3 x y + 4 = 0

- 8 + 3 x^{2} + 2 x = 0

What are the solutions to the equation x^2-1x-12=0 ?
The solutions to the equation x^2-1x-12=0 are x=4,x=-3
Find the zeros of x^2-1x-12=0
The zeros of x^2-1x-12=0 are x=4,x=-3