What are the solutions to the equation 3x^2+11x=-5 ?

The solutions to the equation 3x^2+11x=-5 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6

Find the zeros of 3x^2+11x=-5

The zeros of 3x^2+11x=-5 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6

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3 x^{2} + 11 x = - 5

x = \frac{- 11 + 61}{6}, x = \frac{- 11 - 61}{6}

Decimal Notation

x = - 0.53162 \dots, x = - 3.13504 \dots

Solution steps

3 x^{2} + 11 x = - 5

Move

5

to the left side

3 x^{2} + 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 5 = 61

x_{1, 2} = \frac{- 11 \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 61}{2 \cdot 3}, x_{2} = \frac{- 11 - 61}{2 \cdot 3}

x = \frac{- 11 + 61}{2 \cdot 3} : \frac{- 11 + 61}{6}

x = \frac{- 11 - 61}{2 \cdot 3} : \frac{- 11 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{- 11 + 61}{6}, x = \frac{- 11 - 61}{6}

x, x^{2} + x y + y^{2} - 3 = 0

d^{2} + 8 d + 12 = 0

12 x^{2} + 17 x = 7

2 x^{2} - 5 x - 2 = 0

4.905 t^{2} - 21 t + 12.5 = 0

What are the solutions to the equation 3x^2+11x=-5 ?
The solutions to the equation 3x^2+11x=-5 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6
Find the zeros of 3x^2+11x=-5
The zeros of 3x^2+11x=-5 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6