What are the solutions to the equation (x-7)^2+3(x+8)=2 ?

The solutions to the equation (x-7)^2+3(x+8)=2 are x= 11/2+i(sqrt(163))/2 ,x= 11/2-i(sqrt(163))/2

Find the zeros of (x-7)^2+3(x+8)=2

The zeros of (x-7)^2+3(x+8)=2 are x= 11/2+i(sqrt(163))/2 ,x= 11/2-i(sqrt(163))/2

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(x - 7)^{2} + 3 (x + 8) = 2

x = \frac{11}{2} + i \frac{163}{2}, x = \frac{11}{2} - i \frac{163}{2}

Solution steps

(x - 7)^{2} + 3 (x + 8) = 2

Expand

(x - 7)^{2} + 3 (x + 8) : x^{2} - 11 x + 73

x^{2} - 11 x + 73 = 2

Move

2

to the left side

x^{2} - 11 x + 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 71}{2 \cdot 1}

Simplify

(- 11)^{2} - 4 \cdot 1 \cdot 71 : 163 i

x_{1, 2} = \frac{- ( - 11 ) \pm 163 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 163 i}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 163 i}{2 \cdot 1}

x = \frac{- ( - 11 ) + 163 i}{2 \cdot 1} : \frac{11}{2} + i \frac{163}{2}

x = \frac{- ( - 11 ) - 163 i}{2 \cdot 1} : \frac{11}{2} - i \frac{163}{2}

The solutions to the quadratic equation are:

x = \frac{11}{2} + i \frac{163}{2}, x = \frac{11}{2} - i \frac{163}{2}

8 x^{2} - 4 x - 4 = 0

r, 2 π r^{2} + 2 π r h = A

(x) = x^{2} - x

x^{2} = - 2 x + 48

64 x^{2} + 64 x + 16 = 0

What are the solutions to the equation (x-7)^2+3(x+8)=2 ?
The solutions to the equation (x-7)^2+3(x+8)=2 are x= 11/2+i(sqrt(163))/2 ,x= 11/2-i(sqrt(163))/2
Find the zeros of (x-7)^2+3(x+8)=2
The zeros of (x-7)^2+3(x+8)=2 are x= 11/2+i(sqrt(163))/2 ,x= 11/2-i(sqrt(163))/2