What are the solutions to the equation 9x^2-18x+10=0 ?

The solutions to the equation 9x^2-18x+10=0 are x=1+i 1/3 ,x=1-i 1/3

Find the zeros of 9x^2-18x+10=0

The zeros of 9x^2-18x+10=0 are x=1+i 1/3 ,x=1-i 1/3

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9 x^{2} - 18 x + 10 = 0

x = 1 + i \frac{1}{3}, x = 1 - i \frac{1}{3}

Solution steps

9 x^{2} - 18 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

Simplify

(- 18)^{2} - 4 \cdot 9 \cdot 10 : 6 i

x_{1, 2} = \frac{- ( - 18 ) \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 i}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 i}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 i}{2 \cdot 9} : 1 + i \frac{1}{3}

x = \frac{- ( - 18 ) - 6 i}{2 \cdot 9} : 1 - i \frac{1}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{1}{3}, x = 1 - i \frac{1}{3}

3 x^{2} - 10 x + 9 = 0

(2 x + 3) (x - 2) = 0

7 x^{2} - 1 = 3 x

4.905 t^{2} - 12 t - 70 = 0

2 (x + 9)^{2} = 36

What are the solutions to the equation 9x^2-18x+10=0 ?
The solutions to the equation 9x^2-18x+10=0 are x=1+i 1/3 ,x=1-i 1/3
Find the zeros of 9x^2-18x+10=0
The zeros of 9x^2-18x+10=0 are x=1+i 1/3 ,x=1-i 1/3