What are the solutions to the equation a^2-5a+9=3 ?

The solutions to the equation a^2-5a+9=3 are a=3,a=2

Find the zeros of a^2-5a+9=3

The zeros of a^2-5a+9=3 are a=3,a=2

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a^{2} - 5 a + 9 = 3

a = 3, a = 2

Solution steps

a^{2} - 5 a + 9 = 3

Move

3

to the left side

a^{2} - 5 a + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

a_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

a = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

a = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

a = 3, a = 2

9 + 2.8 x + 5 x^{2} = 78

2 (p - 1) = p (p + 1) - 2

m^{2} - 7 m - 60 = 0

x^{2} + 10 x + 25 = 0

3 x^{2} + 9 = 2 x + 1

What are the solutions to the equation a^2-5a+9=3 ?
The solutions to the equation a^2-5a+9=3 are a=3,a=2
Find the zeros of a^2-5a+9=3
The zeros of a^2-5a+9=3 are a=3,a=2