What are the solutions to the equation -2y^2=8-8y ?

The solutions to the equation -2y^2=8-8y are y=2

Find the zeros of -2y^2=8-8y

The zeros of -2y^2=8-8y are y=2

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- 2 y^{2} = 8 - 8 y

y = 2

Solution steps

- 2 y^{2} = 8 - 8 y

Move

8 y

to the left side

- 2 y^{2} + 8 y = 8

Move

8

to the left side

- 2 y^{2} + 8 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 8) = 0

y_{1, 2} = \frac{- 8 \pm 0}{2 ( - 2 )}

y = \frac{- 8}{2 ( - 2 )}

\frac{- 8}{2 ( - 2 )} = 2

y = 2

The solution to the quadratic equation is:

y = 2

2 x (x - 4) = 3 x + 1

x^{2} - 5 x = 9

(x + 4) (x + 4) = 0

(x + 1)^{2} = \frac{9}{4}

9 y^{2} - 7 y + 4 = 0

What are the solutions to the equation -2y^2=8-8y ?
The solutions to the equation -2y^2=8-8y are y=2
Find the zeros of -2y^2=8-8y
The zeros of -2y^2=8-8y are y=2