What are the solutions to the equation -(x-2)^2-15=-33 ?

The solutions to the equation -(x-2)^2-15=-33 are x=3sqrt(2)+2,x=-3sqrt(2)+2

Find the zeros of -(x-2)^2-15=-33

The zeros of -(x-2)^2-15=-33 are x=3sqrt(2)+2,x=-3sqrt(2)+2

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- (x - 2)^{2} - 15 = - 33

x = 32 + 2, x = - 32 + 2

Decimal Notation

x = 6.24264 \dots, x = - 2.24264 \dots

Solution steps

- (x - 2)^{2} - 15 = - 33

Move

15

to the right side

- (x - 2)^{2} = - 18

Divide both sides by

- 1

(x - 2)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 18 : x = 32 + 2

Solve

x - 2 = - 18 : x = - 32 + 2

The solutions to the quadratic equation are:

x = 32 + 2, x = - 32 + 2

x^{2} + 4 x - 3 = 2 x

w^{2} - 6 w

0 = 3 x^{2} - 8 x

4 x^{2} - 25

y^{2} - 8 y = - 11

What are the solutions to the equation -(x-2)^2-15=-33 ?
The solutions to the equation -(x-2)^2-15=-33 are x=3sqrt(2)+2,x=-3sqrt(2)+2
Find the zeros of -(x-2)^2-15=-33
The zeros of -(x-2)^2-15=-33 are x=3sqrt(2)+2,x=-3sqrt(2)+2