What are the solutions to the equation 4m^2+10m+5=-m ?

The solutions to the equation 4m^2+10m+5=-m are m=(-11+sqrt(41))/8 ,m=(-11-sqrt(41))/8

Find the zeros of 4m^2+10m+5=-m

The zeros of 4m^2+10m+5=-m are m=(-11+sqrt(41))/8 ,m=(-11-sqrt(41))/8

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4 m^{2} + 10 m + 5 = - m

m = \frac{- 11 + 41}{8}, m = \frac{- 11 - 41}{8}

Decimal Notation

m = - 0.57460 \dots, m = - 2.17539 \dots

Solution steps

4 m^{2} + 10 m + 5 = - m

Move

m

to the left side

4 m^{2} + 11 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 \cdot 5 = 41

m_{1, 2} = \frac{- 11 \pm 41}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 11 + 41}{2 \cdot 4}, m_{2} = \frac{- 11 - 41}{2 \cdot 4}

m = \frac{- 11 + 41}{2 \cdot 4} : \frac{- 11 + 41}{8}

m = \frac{- 11 - 41}{2 \cdot 4} : \frac{- 11 - 41}{8}

The solutions to the quadratic equation are:

m = \frac{- 11 + 41}{8}, m = \frac{- 11 - 41}{8}

3 x^{2} + 5 = 4 x^{2} + 3

y^{2} - 2 y + 17 = 0

2 (x - 0.1) (2 x - 1.5) = 0

- y^{2} - y + 2 = 0

(x + 8) (x + 3) = 0

What are the solutions to the equation 4m^2+10m+5=-m ?
The solutions to the equation 4m^2+10m+5=-m are m=(-11+sqrt(41))/8 ,m=(-11-sqrt(41))/8
Find the zeros of 4m^2+10m+5=-m
The zeros of 4m^2+10m+5=-m are m=(-11+sqrt(41))/8 ,m=(-11-sqrt(41))/8