What are the solutions to the equation 4x^2+6x+1.25=0 ?

The solutions to the equation 4x^2+6x+1.25=0 are x=-1/4 ,x=-5/4

Find the zeros of 4x^2+6x+1.25=0

The zeros of 4x^2+6x+1.25=0 are x=-1/4 ,x=-5/4

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4 x^{2} + 6 x + 1.25 = 0

x = - \frac{1}{4}, x = - \frac{5}{4}

Decimal Notation

x = - 0.25, x = - 1.25

Solution steps

4 x^{2} + 6 x + 1.25 = 0

Multiply both sides by

100

400 x^{2} + 600 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 600 \pm 60 0 ^{2} - 4 \cdot 400 \cdot 125}{2 \cdot 400}

60 0^{2} - 4 \cdot 400 \cdot 125 = 400

x_{1, 2} = \frac{- 600 \pm 400}{2 \cdot 400}

Separate the solutions

x_{1} = \frac{- 600 + 400}{2 \cdot 400}, x_{2} = \frac{- 600 - 400}{2 \cdot 400}

x = \frac{- 600 + 400}{2 \cdot 400} : - \frac{1}{4}

x = \frac{- 600 - 400}{2 \cdot 400} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{5}{4}

7 - 8 x - 2 x^{2}

x^{2} - 6 x - 66 = 0

6 x^{(2)} - 3 x = 0

28 x^{2} - 21 x = 0

y, e^{2 x} = 3 y^{2}

What are the solutions to the equation 4x^2+6x+1.25=0 ?
The solutions to the equation 4x^2+6x+1.25=0 are x=-1/4 ,x=-5/4
Find the zeros of 4x^2+6x+1.25=0
The zeros of 4x^2+6x+1.25=0 are x=-1/4 ,x=-5/4