What are the solutions to the equation factor 5y^2-2=-9y ?

The solutions to the equation factor 5y^2-2=-9y are y= 1/5 ,y=-2

Find the zeros of factor 5y^2-2=-9y

The zeros of factor 5y^2-2=-9y are y= 1/5 ,y=-2

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5 y^{2} - 2 = - 9 y

y = \frac{1}{5}, y = - 2

Decimal Notation

y = 0.2, y = - 2

Solution steps

5 y^{2} - 2 = - 9 y

Move

9 y

to the left side

5 y^{2} - 2 + 9 y = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 9 y - 2 = 0

Factor

5 y^{2} + 9 y - 2 : (5 y - 1) (y + 2)

(5 y - 1) (y + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 y - 1 = 0 or y + 2 = 0

Solve

5 y - 1 = 0 : y = \frac{1}{5}

Solve

y + 2 = 0 : y = - 2

The solutions to the quadratic equation are:

y = \frac{1}{5}, y = - 2

4 y^{2} + 9 = - 12 y

2 - y^{2} = 0

x^{2} - 8 x = - 5

3 x^{2} - 12 x = 0

6 x^{2} - 9 x - 8 = 0

What are the solutions to the equation factor 5y^2-2=-9y ?
The solutions to the equation factor 5y^2-2=-9y are y= 1/5 ,y=-2
Find the zeros of factor 5y^2-2=-9y
The zeros of factor 5y^2-2=-9y are y= 1/5 ,y=-2