What are the solutions to the equation completesquare-x^2+4x+12 ?

The solutions to the equation completesquare-x^2+4x+12 are -(x-2)^2+16

Find the zeros of completesquare-x^2+4x+12

The zeros of completesquare-x^2+4x+12 are -(x-2)^2+16

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complete the square

- x^{2} + 4 x + 12

- (x - 2)^{2} + 16

Solution steps

- x^{2} + 4 x + 12

Write

- x^{2} + 4 x + 12

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 4 x - 12)

2 a = - 4 : a = - 2

Add and subtract

(- 2)^{2}

- (x^{2} - 4 x - 12 + (- 2)^{2} - (- 2)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 4 x + (- 2)^{2} = (x - 2)^{2}

- ((x - 2)^{2} - 12 - (- 2)^{2})

Simplify

- (x - 2)^{2} + 16

- 10 x^{2} = 1 x^{2} - 6

2 x^{2} - 3 = 11 x

(x + 6)^{2} = - 2 x

2 x^{2} = 98 x

x^{2} + 3.8 x + 3.61 = 0

What are the solutions to the equation completesquare-x^2+4x+12 ?
The solutions to the equation completesquare-x^2+4x+12 are -(x-2)^2+16
Find the zeros of completesquare-x^2+4x+12
The zeros of completesquare-x^2+4x+12 are -(x-2)^2+16