What are the solutions to the equation x^2+16x+40=0 ?

The solutions to the equation x^2+16x+40=0 are x=2(sqrt(6)-4),x=-2(4+sqrt(6))

Find the zeros of x^2+16x+40=0

The zeros of x^2+16x+40=0 are x=2(sqrt(6)-4),x=-2(4+sqrt(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 16 x + 40 = 0

x = 2 (6 - 4), x = - 2 (4 + 6)

Decimal Notation

x = - 3.10102 \dots, x = - 12.89897 \dots

Solution steps

x^{2} + 16 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 40 = 46

x_{1, 2} = \frac{- 16 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 6}{2 \cdot 1}

x = \frac{- 16 + 4 6}{2 \cdot 1} : 2 (6 - 4)

x = \frac{- 16 - 4 6}{2 \cdot 1} : - 2 (4 + 6)

The solutions to the quadratic equation are:

x = 2 (6 - 4), x = - 2 (4 + 6)

2 x^{2} = - 6 x

2 x^{2} + 8 x = 0

x^{2} + \frac{2}{5} x = 0

3 x^{2} - 6 x + 14 = 0

2 m^{2} + 20 m = - 70

What are the solutions to the equation x^2+16x+40=0 ?
The solutions to the equation x^2+16x+40=0 are x=2(sqrt(6)-4),x=-2(4+sqrt(6))
Find the zeros of x^2+16x+40=0
The zeros of x^2+16x+40=0 are x=2(sqrt(6)-4),x=-2(4+sqrt(6))