What are the solutions to the equation (3x-2)(x+3)=-6x-4 ?

The solutions to the equation (3x-2)(x+3)=-6x-4 are x=(-13+sqrt(193))/6 ,x=(-13-sqrt(193))/6

Find the zeros of (3x-2)(x+3)=-6x-4

The zeros of (3x-2)(x+3)=-6x-4 are x=(-13+sqrt(193))/6 ,x=(-13-sqrt(193))/6

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(3 x - 2) (x + 3) = - 6 x - 4

x = \frac{- 13 + 193}{6}, x = \frac{- 13 - 193}{6}

Decimal Notation

x = 0.14874 \dots, x = - 4.48207 \dots

Solution steps

(3 x - 2) (x + 3) = - 6 x - 4

Expand

(3 x - 2) (x + 3) : 3 x^{2} + 7 x - 6

3 x^{2} + 7 x - 6 = - 6 x - 4

Move

4

to the left side

3 x^{2} + 7 x - 2 = - 6 x

Move

6 x

to the left side

3 x^{2} + 13 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 (- 2) = 193

x_{1, 2} = \frac{- 13 \pm 193}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 193}{2 \cdot 3}, x_{2} = \frac{- 13 - 193}{2 \cdot 3}

x = \frac{- 13 + 193}{2 \cdot 3} : \frac{- 13 + 193}{6}

x = \frac{- 13 - 193}{2 \cdot 3} : \frac{- 13 - 193}{6}

The solutions to the quadratic equation are:

x = \frac{- 13 + 193}{6}, x = \frac{- 13 - 193}{6}

- 1 x^{2} = 8 x^{2} - 5

9 y^{2} - 144 = 0

n^{2} = 17

x^{2} - 1 = 4

4 v^{2} - 64 = 3 v^{2}

What are the solutions to the equation (3x-2)(x+3)=-6x-4 ?
The solutions to the equation (3x-2)(x+3)=-6x-4 are x=(-13+sqrt(193))/6 ,x=(-13-sqrt(193))/6
Find the zeros of (3x-2)(x+3)=-6x-4
The zeros of (3x-2)(x+3)=-6x-4 are x=(-13+sqrt(193))/6 ,x=(-13-sqrt(193))/6