What are the solutions to the equation 3m^2-4m+4=5 ?

The solutions to the equation 3m^2-4m+4=5 are m=(2+sqrt(7))/3 ,m=(2-sqrt(7))/3

Find the zeros of 3m^2-4m+4=5

The zeros of 3m^2-4m+4=5 are m=(2+sqrt(7))/3 ,m=(2-sqrt(7))/3

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3 m^{2} - 4 m + 4 = 5

m = \frac{2 + 7}{3}, m = \frac{2 - 7}{3}

Decimal Notation

m = 1.54858 \dots, m = - 0.21525 \dots

Solution steps

3 m^{2} - 4 m + 4 = 5

Move

5

to the left side

3 m^{2} - 4 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 1) = 27

m_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 3}, m_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 3}

m = \frac{- ( - 4 ) + 2 7}{2 \cdot 3} : \frac{2 + 7}{3}

m = \frac{- ( - 4 ) - 2 7}{2 \cdot 3} : \frac{2 - 7}{3}

The solutions to the quadratic equation are:

m = \frac{2 + 7}{3}, m = \frac{2 - 7}{3}

5 x^{2} + 50 x - 195 = 0

4 x^{2} - 22 x + 10 = 0

10000 = 800 p - 7 p^{2}

5 x^{2} + 8 x - 13 = 0

x^{2} + 4 = 29

What are the solutions to the equation 3m^2-4m+4=5 ?
The solutions to the equation 3m^2-4m+4=5 are m=(2+sqrt(7))/3 ,m=(2-sqrt(7))/3
Find the zeros of 3m^2-4m+4=5
The zeros of 3m^2-4m+4=5 are m=(2+sqrt(7))/3 ,m=(2-sqrt(7))/3