What are the solutions to the equation 4(x^2-5)-1=33 ?

The solutions to the equation 4(x^2-5)-1=33 are x=(3sqrt(3))/(sqrt(2)),x=-(3sqrt(3))/(sqrt(2))

Find the zeros of 4(x^2-5)-1=33

The zeros of 4(x^2-5)-1=33 are x=(3sqrt(3))/(sqrt(2)),x=-(3sqrt(3))/(sqrt(2))

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4 (x^{2} - 5) - 1 = 33

x = \frac{3 3}{2}, x = - \frac{3 3}{2}

Decimal Notation

x = 3.67423 \dots, x = - 3.67423 \dots

Solution steps

4 (x^{2} - 5) - 1 = 33

Move

1

to the right side

4 (x^{2} - 5) = 34

Divide both sides by

4

x^{2} - 5 = \frac{17}{2}

Move

5

to the right side

x^{2} = \frac{27}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{27}{2}, x = - \frac{27}{2}

\frac{27}{2} = \frac{3 3}{2}

- \frac{27}{2} = - \frac{3 3}{2}

x = \frac{3 3}{2}, x = - \frac{3 3}{2}

- 3 x (x - 1) = 8 (3 + x)

4.5 x^{2} = 2.5 (x + 0.5)^{2}

x^{2} + 27 = 12 x

x, x^{2} + x y - y^{2} = - 5

x, (x - 5) (3 x + 2) = 0

What are the solutions to the equation 4(x^2-5)-1=33 ?
The solutions to the equation 4(x^2-5)-1=33 are x=(3sqrt(3))/(sqrt(2)),x=-(3sqrt(3))/(sqrt(2))
Find the zeros of 4(x^2-5)-1=33
The zeros of 4(x^2-5)-1=33 are x=(3sqrt(3))/(sqrt(2)),x=-(3sqrt(3))/(sqrt(2))