What are the solutions to the equation (2x+9)^2=64 ?

The solutions to the equation (2x+9)^2=64 are x=-1/2 ,x=-17/2

Find the zeros of (2x+9)^2=64

The zeros of (2x+9)^2=64 are x=-1/2 ,x=-17/2

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(2 x + 9)^{2} = 64

x = - \frac{1}{2}, x = - \frac{17}{2}

Decimal Notation

x = - 0.5, x = - 8.5

Solution steps

(2 x + 9)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 9 = 64 : x = - \frac{1}{2}

Solve

2 x + 9 = - 64 : x = - \frac{17}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{17}{2}

5 y^{2} = 405

\frac{1}{4} x \frac{1}{2} x = 9

8 y^{2} - y + 7 = 0

x^{2} + 6 x + 7 = 9

0 = 75 + 29 t - 5 t^{2}

What are the solutions to the equation (2x+9)^2=64 ?
The solutions to the equation (2x+9)^2=64 are x=-1/2 ,x=-17/2
Find the zeros of (2x+9)^2=64
The zeros of (2x+9)^2=64 are x=-1/2 ,x=-17/2