What are the solutions to the equation x^2+28x+196=0 ?

The solutions to the equation x^2+28x+196=0 are x=-14

Find the zeros of x^2+28x+196=0

The zeros of x^2+28x+196=0 are x=-14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 28 x + 196 = 0

x = - 14

Solution steps

x^{2} + 28 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 1 \cdot 196}{2 \cdot 1}

2 8^{2} - 4 \cdot 1 \cdot 196 = 0

x_{1, 2} = \frac{- 28 \pm 0}{2 \cdot 1}

x = \frac{- 28}{2 \cdot 1}

\frac{- 28}{2 \cdot 1} = - 14

x = - 14

The solution to the quadratic equation is:

x = - 14

(x + 4)^{2} - 5 = 31

x^{2} + 4 x - 8 = 0

4 x^{2} + 16 x

m, F = \frac{g mm}{d ^{2}}

1 0^{2} + b^{2} = 1 5^{2}

What are the solutions to the equation x^2+28x+196=0 ?
The solutions to the equation x^2+28x+196=0 are x=-14
Find the zeros of x^2+28x+196=0
The zeros of x^2+28x+196=0 are x=-14