What are the solutions to the equation solvefor x,(x+y)(x+y)=1 ?

The solutions to the equation solvefor x,(x+y)(x+y)=1 are x=1-y,x=-1-y

Find the zeros of solvefor x,(x+y)(x+y)=1

The zeros of solvefor x,(x+y)(x+y)=1 are x=1-y,x=-1-y

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solve for

x, (x + y) (x + y) = 1

x = 1 - y, x = - 1 - y

Solution steps

(x + y) (x + y) = 1

Simplify

(x + y)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + y = 1 : x = 1 - y

Solve

x + y = - 1 : x = - 1 - y

The solutions to the quadratic equation are:

x = 1 - y, x = - 1 - y

x^{2} - 2 x - 35 = 0

3 h^{2} = 147

2 x^{2} + 3 x + 4

(x - 8) (x + 4) = (x - 4 x) (x - 3)

x, s (x) = x^{2} - 8 x + 15

What are the solutions to the equation solvefor x,(x+y)(x+y)=1 ?
The solutions to the equation solvefor x,(x+y)(x+y)=1 are x=1-y,x=-1-y
Find the zeros of solvefor x,(x+y)(x+y)=1
The zeros of solvefor x,(x+y)(x+y)=1 are x=1-y,x=-1-y