What are the solutions to the equation -5x^2-40x=-320 ?

The solutions to the equation -5x^2-40x=-320 are x=-4(1+sqrt(5)),x=4(sqrt(5)-1)

Find the zeros of -5x^2-40x=-320

The zeros of -5x^2-40x=-320 are x=-4(1+sqrt(5)),x=4(sqrt(5)-1)

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- 5 x^{2} - 40 x = - 320

x = - 4 (1 + 5), x = 4 (5 - 1)

Decimal Notation

x = - 12.94427 \dots, x = 4.94427 \dots

Solution steps

- 5 x^{2} - 40 x = - 320

Move

320

to the left side

- 5 x^{2} - 40 x + 320 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 5 ) \cdot 320}{2 ( - 5 )}

(- 40)^{2} - 4 (- 5) \cdot 320 = 405

x_{1, 2} = \frac{- ( - 40 ) \pm 40 5}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 40 5}{2 ( - 5 )}, x_{2} = \frac{- ( - 40 ) - 40 5}{2 ( - 5 )}

x = \frac{- ( - 40 ) + 40 5}{2 ( - 5 )} : - 4 (1 + 5)

x = \frac{- ( - 40 ) - 40 5}{2 ( - 5 )} : 4 (5 - 1)

The solutions to the quadratic equation are:

x = - 4 (1 + 5), x = 4 (5 - 1)

y^{2} - 5 y - 5 = - 2 y

x^{2} - 3 x + 4 = 0

10 x^{2} - 12 x = 15

7 - 3 x^{2} = 0

10 x^{2} - 13 x + 4 = 0

What are the solutions to the equation -5x^2-40x=-320 ?
The solutions to the equation -5x^2-40x=-320 are x=-4(1+sqrt(5)),x=4(sqrt(5)-1)
Find the zeros of -5x^2-40x=-320
The zeros of -5x^2-40x=-320 are x=-4(1+sqrt(5)),x=4(sqrt(5)-1)