What are the solutions to the equation (2x+2)^2=16 ?

The solutions to the equation (2x+2)^2=16 are x=1,x=-3

Find the zeros of (2x+2)^2=16

The zeros of (2x+2)^2=16 are x=1,x=-3

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(2 x + 2)^{2} = 16

x = 1, x = - 3

Solution steps

(2 x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 2 = 16 : x = 1

Solve

2 x + 2 = - 16 : x = - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

(x^{2} + a x - 10) (1 - a) = (2 a + 6) (1 - x)

14 x - 7 x^{2} = 0

x^{2} + 10 = 4 x - 2

z^{2} + 6 z

x^{2} + 4 x + 19 = 0

What are the solutions to the equation (2x+2)^2=16 ?
The solutions to the equation (2x+2)^2=16 are x=1,x=-3
Find the zeros of (2x+2)^2=16
The zeros of (2x+2)^2=16 are x=1,x=-3