What is (2x^4y^{-4}z^{-3})/(3x^2y^{-3)z^4} ?

The solution to (2x^4y^{-4}z^{-3})/(3x^2y^{-3)z^4} is (2x^2)/(3yz^7)

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simplify (2x^4y^{-4}z^{-3})/(3x^2y^{-3)z^4}

simplify

\frac{2 x ^{4} y ^{- 4} z ^{- 3}}{3 x ^{2} y ^{- 3} z ^{4}}

\frac{2 x ^{2}}{3 y z ^{7}}

Solution steps

\frac{2 x ^{4} y ^{- 4} z ^{- 3}}{3 x ^{2} y ^{- 3} z ^{4}}

Simplify

\frac{x ^{4}}{x ^{2}} : x^{2}

= \frac{2 x ^{2} y ^{- 4} z ^{- 3}}{3 y ^{- 3} z ^{4}}

Simplify

\frac{y ^{- 4}}{y ^{- 3}} : \frac{1}{y}

= \frac{2 x ^{2} z ^{- 3}}{3 y z ^{4}}

Simplify

\frac{z ^{- 3}}{z ^{4}} : \frac{1}{z ^{7}}

= \frac{2 x ^{2}}{3 y z ^{7}}

\frac{49}{4}

x = \frac{30 ( 900 )}{( \frac{π 1 6 ^{2}}{4} ) ( 120 )}

y - x^{5} y^{4}

4 - \frac{2 x}{3} = 0

(x + 4) (x + 5) (x - 3) \leq 0

What is (2x^4y^{-4}z^{-3})/(3x^2y^{-3)z^4} ?
The solution to (2x^4y^{-4}z^{-3})/(3x^2y^{-3)z^4} is (2x^2)/(3yz^7)