What are the solutions to the equation x^2-(-2)x-24=0 ?

The solutions to the equation x^2-(-2)x-24=0 are x=4,x=-6

Find the zeros of x^2-(-2)x-24=0

The zeros of x^2-(-2)x-24=0 are x=4,x=-6

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x^{2} - (- 2) x - 24 = 0

x = 4, x = - 6

Solution steps

x^{2} - (- 2) x - 24 = 0

Refine

x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 10}{2 \cdot 1}

x = \frac{- 2 + 10}{2 \cdot 1} : 4

x = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 4, x = - 6

n^{2} + 9 n + 14 = 0

x^{2} + 3.9 x + 6.8 = 0

\frac{a + 3 x ^{2}}{b} = x^{2}

2 x^{2} + 2 x - 1

x^{2} + 2 x - 6 = 0

What are the solutions to the equation x^2-(-2)x-24=0 ?
The solutions to the equation x^2-(-2)x-24=0 are x=4,x=-6
Find the zeros of x^2-(-2)x-24=0
The zeros of x^2-(-2)x-24=0 are x=4,x=-6