What are the solutions to the equation x^2+7=2x ?

The solutions to the equation x^2+7=2x are x=1+sqrt(6)i,x=1-sqrt(6)i

Find the zeros of x^2+7=2x

The zeros of x^2+7=2x are x=1+sqrt(6)i,x=1-sqrt(6)i

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x^{2} + 7 = 2 x

x = 1 + 6 i, x = 1 - 6 i

Solution steps

x^{2} + 7 = 2 x

Move

2 x

to the left side

x^{2} + 7 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 7 : 26 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6 i}{2 \cdot 1} : 1 + 6 i

x = \frac{- ( - 2 ) - 2 6 i}{2 \cdot 1} : 1 - 6 i

The solutions to the quadratic equation are:

x = 1 + 6 i, x = 1 - 6 i

5 b^{2} - 36 b = 32

(2 y - 1)^{2} - (2 y - 1) y + y^{2} - 7 = 0

x^{2} + a x - 8 = 0

3 x^{2} - 2 x - 2 = 0

5 y^{2} + 1 = 21

What are the solutions to the equation x^2+7=2x ?
The solutions to the equation x^2+7=2x are x=1+sqrt(6)i,x=1-sqrt(6)i
Find the zeros of x^2+7=2x
The zeros of x^2+7=2x are x=1+sqrt(6)i,x=1-sqrt(6)i