What are the solutions to the equation x^2+(-1)^2+2x+4(-1)+2=0 ?

The solutions to the equation x^2+(-1)^2+2x+4(-1)+2=0 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x^2+(-1)^2+2x+4(-1)+2=0

The zeros of x^2+(-1)^2+2x+4(-1)+2=0 are x=-1+sqrt(2),x=-1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + (- 1)^{2} + 2 x + 4 (- 1) + 2 = 0

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x^{2} + (- 1)^{2} + 2 x + 4 (- 1) + 2 = 0

Expand

x^{2} + (- 1)^{2} + 2 x + 4 (- 1) + 2 : x^{2} + 2 x - 1

x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

x = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

x = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

9 x^{2} = 121

9 x^{2} = 18 x

h^{2} + 2 h - 5 = 0

x, x^{2} - x - 56 = 0

x, 2 x^{2} - 4 x y + 3 y^{2} = 1

What are the solutions to the equation x^2+(-1)^2+2x+4(-1)+2=0 ?
The solutions to the equation x^2+(-1)^2+2x+4(-1)+2=0 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x^2+(-1)^2+2x+4(-1)+2=0
The zeros of x^2+(-1)^2+2x+4(-1)+2=0 are x=-1+sqrt(2),x=-1-sqrt(2)